20-2400/x^2=0

Solution for 20-2400/x^2=0 equation:

20-2400/x^2=0


Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


20*x^2-2400=0

We add all the numbers together, and all the variables

20x^2-2400=0

a = 20; b = 0; c = -2400;
Δ = b2-4ac
Δ = 02-4·20·(-2400)
Δ = 192000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192000}=\sqrt{6400*30}=\sqrt{6400}*\sqrt{30}=80\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{30}}{2*20}=\frac{0-80\sqrt{30}}{40}
=-\frac{80\sqrt{30}}{40}
=-2\sqrt{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{30}}{2*20}=\frac{0+80\sqrt{30}}{40}
=\frac{80\sqrt{30}}{40}
=2\sqrt{30}
$